Search a number
-
+
3111020121201 = 31037006707067
BaseRepresentation
bin101101010001010111001…
…111111100110001110001
3102000102002100012210000220
4231101113033330301301
5401432332122334301
610341103302003253
7440522656500606
oct55212717746161
912012070183026
103111020121201
11a9a415832a63
12422b2a416529
131974a2490605
14aa8077846ad
1555dd1194936
hex2d4573fcc71

3111020121201 has 4 divisors (see below), whose sum is σ = 4148026828272. Its totient is φ = 2074013414132.

The previous prime is 3111020121193. The next prime is 3111020121233. The reversal of 3111020121201 is 1021210201113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3111020121201 - 23 = 3111020121193 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3111020121101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 518503353531 + ... + 518503353536.

It is an arithmetic number, because the mean of its divisors is an integer number (1037006707068).

Almost surely, 23111020121201 is an apocalyptic number.

It is an amenable number.

3111020121201 is a deficient number, since it is larger than the sum of its proper divisors (1037006707071).

3111020121201 is a wasteful number, since it uses less digits than its factorization.

3111020121201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1037006707070.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 3111020121201 its reverse (1021210201113), we get a palindrome (4132230322314).

The spelling of 3111020121201 in words is "three trillion, one hundred eleven billion, twenty million, one hundred twenty-one thousand, two hundred one".

Divisors: 1 3 1037006707067 3111020121201