Base | Representation |
---|---|
bin | 101101010001010111111… |
… | …010101010111010011111 |
3 | 102000102010010021202012111 |
4 | 231101113322222322133 |
5 | 401432343004221343 |
6 | 10341104342014451 |
7 | 440523153623041 |
oct | 55212772527237 |
9 | 12012103252174 |
10 | 3111031320223 |
11 | a9a421091a52 |
12 | 422b32117427 |
13 | 1974a48b1b58 |
14 | aa80905ba91 |
15 | 55dd2157c9d |
hex | 2d457eaae9f |
3111031320223 has 4 divisors (see below), whose sum is σ = 3111283789848. Its totient is φ = 3110778850600.
The previous prime is 3111031320211. The next prime is 3111031320247. The reversal of 3111031320223 is 3220231301113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3111031320223 - 213 = 3111031312031 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3111031320194 and 3111031320203.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3111031320283) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 126216328 + ... + 126240973.
It is an arithmetic number, because the mean of its divisors is an integer number (777820947462).
Almost surely, 23111031320223 is an apocalyptic number.
3111031320223 is a deficient number, since it is larger than the sum of its proper divisors (252469625).
3111031320223 is a wasteful number, since it uses less digits than its factorization.
3111031320223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 252469624.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 3111031320223 its reverse (3220231301113), we get a palindrome (6331262621336).
The spelling of 3111031320223 in words is "three trillion, one hundred eleven billion, thirty-one million, three hundred twenty thousand, two hundred twenty-three".
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