311104020023 has 4 divisors (see below), whose sum is σ = 311107312560. Its totient is φ = 311100727488.

The previous prime is 311104020013. The next prime is 311104020049. The reversal of 311104020023 is 320020401113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 311104020023 - 2¹⁰ = 311104018999 is a prime.

It is a super-2 number, since 2×311104020023² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 311104019983 and 311104020010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311104020013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1500218 + ... + 1694951.

It is an arithmetic number, because the mean of its divisors is an integer number (77776828140).

Almost surely, 2^311104020023 is an apocalyptic number.

311104020023 is a deficient number, since it is larger than the sum of its proper divisors (3292537).

311104020023 is an equidigital number, since it uses as much as digits as its factorization.

311104020023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3292536.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 311104020023 its reverse (320020401113), we get a palindrome (631124421136).

The spelling of 311104020023 in words is "three hundred eleven billion, one hundred four million, twenty thousand, twenty-three".