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31111013023 = 252431232461
BaseRepresentation
bin11100111110010111…
…000110001010011111
32222022011212012201121
4130332113012022133
51002203404404043
622143040551411
72150650150606
oct347627061237
988264765647
1031111013023
11122153a0612
126043022567
132c1a60075c
141711c12a3d
15c21437ded
hex73e5c629f

31111013023 has 4 divisors (see below), whose sum is σ = 31112270728. Its totient is φ = 31109755320.

The previous prime is 31111012981. The next prime is 31111013029. The reversal of 31111013023 is 32031011113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 31111013023 - 217 = 31110881951 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31111012988 and 31111013006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31111013029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 590988 + ... + 641473.

It is an arithmetic number, because the mean of its divisors is an integer number (7778067682).

Almost surely, 231111013023 is an apocalyptic number.

31111013023 is a deficient number, since it is larger than the sum of its proper divisors (1257705).

31111013023 is a wasteful number, since it uses less digits than its factorization.

31111013023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1257704.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 31111013023 its reverse (32031011113), we get a palindrome (63142024136).

The spelling of 31111013023 in words is "thirty-one billion, one hundred eleven million, thirteen thousand, twenty-three".

Divisors: 1 25243 1232461 31111013023