311112233332013 has 4 divisors (see below), whose sum is σ = 311112362443008. Its totient is φ = 311112104221020.

The previous prime is 311112233331979. The next prime is 311112233332067. The reversal of 311112233332013 is 310233332211113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-311112233332013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311112233332913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60870923 + ... + 65783688.

It is an arithmetic number, because the mean of its divisors is an integer number (77778090610752).

Almost surely, 2^{311112233332013} is an apocalyptic number.

It is an amenable number.

311112233332013 is a deficient number, since it is larger than the sum of its proper divisors (129110995).

311112233332013 is a wasteful number, since it uses less digits than its factorization.

311112233332013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 129110994.

The product of its (nonzero) digits is 5832, while the sum is 29.

Adding to 311112233332013 its reverse (310233332211113), we get a palindrome (621345565543126).

The spelling of 311112233332013 in words is "three hundred eleven trillion, one hundred twelve billion, two hundred thirty-three million, three hundred thirty-two thousand, thirteen".