3111141331 has 4 divisors (see below), whose sum is σ = 3163872600. Its totient is φ = 3058410064.

The previous prime is 3111141323. The next prime is 3111141343. The reversal of 3111141331 is 1331411113.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1331411113 = 563 ⋅2364851.

It is a cyclic number.

It is not a de Polignac number, because 3111141331 - 2³ = 3111141323 is a prime.

It is a super-2 number, since 2×3111141331² = 19358400762912903122, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3111141299 and 3111141308.

It is not an unprimeable number, because it can be changed into a prime (3111141311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26365546 + ... + 26365663.

It is an arithmetic number, because the mean of its divisors is an integer number (790968150).

Almost surely, 2^3111141331 is an apocalyptic number.

3111141331 is a deficient number, since it is larger than the sum of its proper divisors (52731269).

3111141331 is an equidigital number, since it uses as much as digits as its factorization.

3111141331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52731268.

The product of its digits is 108, while the sum is 19.

The square root of 3111141331 is about 55777.6059991821. The cubic root of 3111141331 is about 1459.8444400157.

Adding to 3111141331 its reverse (1331411113), we get a palindrome (4442552444).

It can be divided in two parts, 311114 and 1331, that added together give a triangular number (312445 = T₇₉₀).

The spelling of 3111141331 in words is "three billion, one hundred eleven million, one hundred forty-one thousand, three hundred thirty-one".