31112021114 has 4 divisors (see below), whose sum is σ = 46668031674. Its totient is φ = 15556010556.

The previous prime is 31112021093. The next prime is 31112021131. The reversal of 31112021114 is 41112021113.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41112021113 = 5683 ⋅7234211.

It can be written as a sum of positive squares in only one way, i.e., 22475106889 + 8636914225 = 149917^2 + 92935^2 .

It is a junction number, because it is equal to n+sod(n) for n = 31112021092 and 31112021101.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7778005277 + ... + 7778005280.

Almost surely, 2^31112021114 is an apocalyptic number.

31112021114 is a deficient number, since it is larger than the sum of its proper divisors (15556010560).

31112021114 is a wasteful number, since it uses less digits than its factorization.

31112021114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15556010559.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 31112021114 its reverse (41112021113), we get a palindrome (72224042227).

Subtracting 31112021114 from its reverse (41112021113), we obtain a palindrome (9999999999).

The spelling of 31112021114 in words is "thirty-one billion, one hundred twelve million, twenty-one thousand, one hundred fourteen".