3111212121231 has 4 divisors (see below), whose sum is σ = 4148282828312. Its totient is φ = 2074141414152.

The previous prime is 3111212121209. The next prime is 3111212121247. The reversal of 3111212121231 is 1321212121113.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 3111212121231 - 2⁹ = 3111212120719 is a prime.

It is a super-4 number, since 4×3111212121231⁴ (a number of 51 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3111212121198 and 3111212121207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3111212121431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 518535353536 + ... + 518535353541.

It is an arithmetic number, because the mean of its divisors is an integer number (1037070707078).

Almost surely, 2^{3111212121231} is an apocalyptic number.

3111212121231 is a deficient number, since it is larger than the sum of its proper divisors (1037070707081).

3111212121231 is a wasteful number, since it uses less digits than its factorization.

3111212121231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1037070707080.

The product of its digits is 144, while the sum is 21.

Adding to 3111212121231 its reverse (1321212121113), we get a palindrome (4432424242344).

The spelling of 3111212121231 in words is "three trillion, one hundred eleven billion, two hundred twelve million, one hundred twenty-one thousand, two hundred thirty-one".