Base | Representation |
---|---|
bin | 1110001001011110110111… |
… | …01001011100110110010101 |
3 | 11002011021212001112000101211 |
4 | 13010233123221130312111 |
5 | 13034220122044420201 |
6 | 150100414445221421 |
7 | 6360530443543405 |
oct | 704573351346625 |
9 | 132137761460354 |
10 | 31112133201301 |
11 | 9a05644111839 |
12 | 35a58a6561871 |
13 | 1448b27b48979 |
14 | 797b9a026805 |
15 | 38e470a5c651 |
hex | 1c4bdba5cd95 |
31112133201301 has 4 divisors (see below), whose sum is σ = 31163388775552. Its totient is φ = 31060877627052.
The previous prime is 31112133201217. The next prime is 31112133201343. The reversal of 31112133201301 is 10310233121113.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 31112133201301 - 217 = 31112133070229 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31112133211301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25627786215 + ... + 25627787428.
It is an arithmetic number, because the mean of its divisors is an integer number (7790847193888).
Almost surely, 231112133201301 is an apocalyptic number.
It is an amenable number.
31112133201301 is a deficient number, since it is larger than the sum of its proper divisors (51255574251).
31112133201301 is an equidigital number, since it uses as much as digits as its factorization.
31112133201301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51255574250.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 31112133201301 its reverse (10310233121113), we get a palindrome (41422366322414).
The spelling of 31112133201301 in words is "thirty-one trillion, one hundred twelve billion, one hundred thirty-three million, two hundred one thousand, three hundred one".
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