3111241013 has 4 divisors (see below), whose sum is σ = 3274990560. Its totient is φ = 2947491468.

The previous prime is 3111240997. The next prime is 3111241039. The reversal of 3111241013 is 3101421113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3101421113 = 7 ⋅443060159.

It is a cyclic number.

It is not a de Polignac number, because 3111241013 - 2⁴ = 3111240997 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3111240982 and 3111241000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3111241813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81874745 + ... + 81874782.

It is an arithmetic number, because the mean of its divisors is an integer number (818747640).

Almost surely, 2^3111241013 is an apocalyptic number.

It is an amenable number.

3111241013 is a deficient number, since it is larger than the sum of its proper divisors (163749547).

3111241013 is a wasteful number, since it uses less digits than its factorization.

3111241013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163749546.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 3111241013 is about 55778.4995585217. The cubic root of 3111241013 is about 1459.8600311492.

Adding to 3111241013 its reverse (3101421113), we get a palindrome (6212662126).

The spelling of 3111241013 in words is "three billion, one hundred eleven million, two hundred forty-one thousand, thirteen".