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31112441141 = 168643184487
BaseRepresentation
bin11100111110011100…
…100010110100110101
32222022021112202201212
4130332130202310311
51002204241104031
622143131331205
72150665246325
oct347634426465
988267482655
1031112441141
1112216186581
1260435b0b05
132c1a9b07b2
1417120a5285
15c2161b12b
hex73e722d35

31112441141 has 4 divisors (see below), whose sum is σ = 31112794272. Its totient is φ = 31112088012.

The previous prime is 31112441137. The next prime is 31112441147. The reversal of 31112441141 is 14114421113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 31112441141 - 22 = 31112441137 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31112441147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76400 + ... + 260886.

It is an arithmetic number, because the mean of its divisors is an integer number (7778198568).

Almost surely, 231112441141 is an apocalyptic number.

It is an amenable number.

31112441141 is a deficient number, since it is larger than the sum of its proper divisors (353131).

31112441141 is a wasteful number, since it uses less digits than its factorization.

31112441141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 353130.

The product of its digits is 384, while the sum is 23.

Adding to 31112441141 its reverse (14114421113), we get a palindrome (45226862254).

The spelling of 31112441141 in words is "thirty-one billion, one hundred twelve million, four hundred forty-one thousand, one hundred forty-one".

Divisors: 1 168643 184487 31112441141