Base | Representation |
---|---|
bin | 1110001001100000011110… |
… | …10100001000111110010111 |
3 | 11002011101002110121110222021 |
4 | 13010300033110020332113 |
5 | 13034223411001430403 |
6 | 150101040452314011 |
7 | 6360561100505155 |
oct | 704601724107627 |
9 | 132141073543867 |
10 | 31113000030103 |
11 | 9a05a49448082 |
12 | 35a5aa8912907 |
13 | 1448c355c9b14 |
14 | 797c3d1ca3d5 |
15 | 38e4c1bd58bd |
hex | 1c4c0f508f97 |
31113000030103 has 4 divisors (see below), whose sum is σ = 32943176502480. Its totient is φ = 29282823557728.
The previous prime is 31113000030041. The next prime is 31113000030107. The reversal of 31113000030103 is 30103000031113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31113000030103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31113000030107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 915088236163 + ... + 915088236196.
It is an arithmetic number, because the mean of its divisors is an integer number (8235794125620).
Almost surely, 231113000030103 is an apocalyptic number.
31113000030103 is a deficient number, since it is larger than the sum of its proper divisors (1830176472377).
31113000030103 is a wasteful number, since it uses less digits than its factorization.
31113000030103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1830176472376.
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 31113000030103 its reverse (30103000031113), we get a palindrome (61216000061216).
The spelling of 31113000030103 in words is "thirty-one trillion, one hundred thirteen billion, thirty thousand, one hundred three".
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