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311130313131 = 31154071743701
BaseRepresentation
bin1001000011100001100…
…11111101000110101011
31002202002012120111222210
410201300303331012223
520044143330010011
6354533054220203
731323046012011
oct4416063750653
91082065514883
10311130313131
1110aa49a502a0
1250370ab4663
1323454a51401
14110b74548b1
15815e8de6a6
hex4870cfd1ab

311130313131 has 16 divisors (see below), whose sum is σ = 452637139968. Its totient is φ = 188528844000.

The previous prime is 311130313093. The next prime is 311130313147. The reversal of 311130313131 is 131313031113.

It is not a de Polignac number, because 311130313131 - 27 = 311130313003 is a prime.

It is a super-2 number, since 2×3111303131312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 311130313098 and 311130313107.

It is not an unprimeable number, because it can be changed into a prime (311130313231) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 693420 + ... + 1050281.

It is an arithmetic number, because the mean of its divisors is an integer number (28289821248).

Almost surely, 2311130313131 is an apocalyptic number.

311130313131 is a deficient number, since it is larger than the sum of its proper divisors (141506826837).

311130313131 is a wasteful number, since it uses less digits than its factorization.

311130313131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1749122.

The product of its (nonzero) digits is 243, while the sum is 21.

Adding to 311130313131 its reverse (131313031113), we get a palindrome (442443344244).

The spelling of 311130313131 in words is "three hundred eleven billion, one hundred thirty million, three hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 3 11 33 5407 16221 59477 178431 1743701 5231103 19180711 57542133 9428191307 28284573921 103710104377 311130313131