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31113102113 = 891392515003
BaseRepresentation
bin11100111110011111…
…000100001100100001
32222022022210100102022
4130332133010030201
51002204423231423
622143153431225
72151004001342
oct347637041441
988268710368
1031113102113
1112216598135
12604386b515
132c1ab825c2
1417121d80c9
15c216ebdc8
hex73e7c4321

31113102113 has 8 divisors (see below), whose sum is σ = 31689050400. Its totient is φ = 30542184288.

The previous prime is 31113102107. The next prime is 31113102157. The reversal of 31113102113 is 31120131113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 31113102113 - 26 = 31113102049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31113102091 and 31113102100.

It is not an unprimeable number, because it can be changed into a prime (31113102103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1245131 + ... + 1269872.

It is an arithmetic number, because the mean of its divisors is an integer number (3961131300).

Almost surely, 231113102113 is an apocalyptic number.

It is an amenable number.

31113102113 is a deficient number, since it is larger than the sum of its proper divisors (575948287).

31113102113 is a wasteful number, since it uses less digits than its factorization.

31113102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2515231.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 31113102113 its reverse (31120131113), we get a palindrome (62233233226).

The spelling of 31113102113 in words is "thirty-one billion, one hundred thirteen million, one hundred two thousand, one hundred thirteen".

Divisors: 1 89 139 12371 2515003 223835267 349585417 31113102113