31120131113 has 4 divisors (see below), whose sum is σ = 31214149968. Its totient is φ = 31026112260.

The previous prime is 31120131089. The next prime is 31120131157. The reversal of 31120131113 is 31113102113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31120131113 - 2⁸ = 31120130857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31120131091 and 31120131100.

It is not an unprimeable number, because it can be changed into a prime (31120161113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47008931 + ... + 47009592.

It is an arithmetic number, because the mean of its divisors is an integer number (7803537492).

Almost surely, 2^31120131113 is an apocalyptic number.

It is an amenable number.

31120131113 is a deficient number, since it is larger than the sum of its proper divisors (94018855).

31120131113 is an equidigital number, since it uses as much as digits as its factorization.

31120131113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94018854.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 31120131113 its reverse (31113102113), we get a palindrome (62233233226).

The spelling of 31120131113 in words is "thirty-one billion, one hundred twenty million, one hundred thirty-one thousand, one hundred thirteen".