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3111311242145 = 54799469133103
BaseRepresentation
bin101101010001101000100…
…110011111001110100001
3102000102211122000020220002
4231101220212133032201
5401433431134222040
610341152221425345
7440533123126661
oct55215046371641
912012748006802
103111311242145
11a9a5550a2487
12422baba0b255
1319751a89cb22
14aa8342c61a1
1555deb9eca15
hex2d46899f3a1

3111311242145 has 16 divisors (see below), whose sum is σ = 3813078205440. Its totient is φ = 2436047711424.

The previous prime is 3111311242139. The next prime is 3111311242189. The reversal of 3111311242145 is 5412421131113.

3111311242145 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 3111311242145 - 210 = 3111311241121 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23308664 + ... + 23441766.

It is an arithmetic number, because the mean of its divisors is an integer number (238317387840).

Almost surely, 23111311242145 is an apocalyptic number.

It is an amenable number.

3111311242145 is a deficient number, since it is larger than the sum of its proper divisors (701766963295).

3111311242145 is a wasteful number, since it uses less digits than its factorization.

3111311242145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 232624.

The product of its digits is 2880, while the sum is 29.

Adding to 3111311242145 its reverse (5412421131113), we get a palindrome (8523732373258).

The spelling of 3111311242145 in words is "three trillion, one hundred eleven billion, three hundred eleven million, two hundred forty-two thousand, one hundred forty-five".

Divisors: 1 5 47 235 99469 133103 497345 665515 4675043 6255841 23375215 31279205 13239622307 66198111535 622262248429 3111311242145