Base | Representation |
---|---|
bin | 101101010001101001000… |
… | …110101100110001010111 |
3 | 102000102212012220021000000 |
4 | 231101221012230301113 |
5 | 401433440314424411 |
6 | 10341153122422343 |
7 | 440533254656211 |
oct | 55215106546127 |
9 | 12012765807000 |
10 | 3111319686231 |
11 | a9a55993a669 |
12 | 422bb28019b3 |
13 | 19751c568423 |
14 | aa8354835b1 |
15 | 55dec619956 |
hex | 2d4691acc57 |
3111319686231 has 14 divisors (see below), whose sum is σ = 4664845566320. Its totient is φ = 2074213123668.
The previous prime is 3111319686227. The next prime is 3111319686253. The reversal of 3111319686231 is 1326869131113.
3111319686231 is a `hidden beast` number, since 3 + 1 + 1 + 1 + 3 + 19 + 6 + 8 + 623 + 1 = 666.
3111319686231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3111319686231 - 22 = 3111319686227 is a prime.
It is a super-2 number, since 2×31113196862312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3111319682231) by changing a digit.
It is a polite number, since it can be written in 13 ways as a sum of consecutive naturals, for example, 2133963391 + ... + 2133964848.
Almost surely, 23111319686231 is an apocalyptic number.
3111319686231 is a deficient number, since it is larger than the sum of its proper divisors (1553525880089).
3111319686231 is an frugal number, since it uses more digits than its factorization.
3111319686231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4267928257 (or 4267928242 counting only the distinct ones).
The product of its digits is 139968, while the sum is 45.
The spelling of 3111319686231 in words is "three trillion, one hundred eleven billion, three hundred nineteen million, six hundred eighty-six thousand, two hundred thirty-one".
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