3111320231114 has 4 divisors (see below), whose sum is σ = 4666980346674. Its totient is φ = 1555660115556.

The previous prime is 3111320231101. The next prime is 3111320231137. The reversal of 3111320231114 is 4111320231113.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 2870764314889 + 240555916225 = 1694333^2 + 490465^2 .

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 3111320231114.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 777830057777 + ... + 777830057780.

Almost surely, 2^{3111320231114} is an apocalyptic number.

3111320231114 is a deficient number, since it is larger than the sum of its proper divisors (1555660115560).

3111320231114 is a wasteful number, since it uses less digits than its factorization.

3111320231114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1555660115559.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 3111320231114 its reverse (4111320231113), we get a palindrome (7222640462227).

Subtracting 3111320231114 from its reverse (4111320231113), we obtain a palindrome (999999999999).

The spelling of 3111320231114 in words is "three trillion, one hundred eleven billion, three hundred twenty million, two hundred thirty-one thousand, one hundred fourteen".