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3111322541242 = 21555661270621
BaseRepresentation
bin101101010001101001010…
…001100101110010111010
3102000102212102021022100011
4231101221101211302322
5401433442032304432
610341153303532134
7440533321146646
oct55215121456272
912012772238304
103111322541242
11a9a56050a683
12422bb375a04a
13197520027a96
14aa8359c7c26
1555dec9d0847
hex2d469465cba

3111322541242 has 4 divisors (see below), whose sum is σ = 4666983811866. Its totient is φ = 1555661270620.

The previous prime is 3111322541147. The next prime is 3111322541263. The reversal of 3111322541242 is 2421452231113.

3111322541242 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 2323792311201 + 787530230041 = 1524399^2 + 887429^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 777830635309 + ... + 777830635312.

Almost surely, 23111322541242 is an apocalyptic number.

3111322541242 is a deficient number, since it is larger than the sum of its proper divisors (1555661270624).

3111322541242 is a wasteful number, since it uses less digits than its factorization.

3111322541242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1555661270623.

The product of its digits is 11520, while the sum is 31.

Adding to 3111322541242 its reverse (2421452231113), we get a palindrome (5532774772355).

The spelling of 3111322541242 in words is "three trillion, one hundred eleven billion, three hundred twenty-two million, five hundred forty-one thousand, two hundred forty-two".

Divisors: 1 2 1555661270621 3111322541242