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31115140000 = 255471092039
BaseRepresentation
bin11100111110100110…
…110101101110100000
32222022110121212212121
4130332212311232200
51002210433440000
622143305234024
72151030216610
oct347646655640
988273555777
1031115140000
111221775a23a
126044492914
132c1b417059
1417125a8a40
15c219a0b1a
hex73e9b5ba0

31115140000 has 240 divisors, whose sum is σ = 88329225600. Its totient is φ = 10564992000.

The previous prime is 31115139997. The next prime is 31115140019. The reversal of 31115140000 is 4151113.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 15258981 + ... + 15261019.

It is an arithmetic number, because the mean of its divisors is an integer number (368038440).

Almost surely, 231115140000 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31115140000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (44164612800).

31115140000 is an abundant number, since it is smaller than the sum of its proper divisors (57214085600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31115140000 is a wasteful number, since it uses less digits than its factorization.

31115140000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2185 (or 2162 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 31115140000 its reverse (4151113), we get a palindrome (31119291113).

The spelling of 31115140000 in words is "thirty-one billion, one hundred fifteen million, one hundred forty thousand".