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311202202114 = 2155601101057
BaseRepresentation
bin1001000011101010001…
…10001100001000000010
31002202021012211212010201
410201311012030020002
520044320230431424
6354544143115414
731324611033616
oct4416506141002
91082235755121
10311202202114
1110aa86591581
1250390ba2b6a
132346690197b
14110c2c09346
158165d8ed44
hex487518c202

311202202114 has 4 divisors (see below), whose sum is σ = 466803303174. Its totient is φ = 155601101056.

The previous prime is 311202202081. The next prime is 311202202117. The reversal of 311202202114 is 411202202113.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 311202201025 + 1089 = 557855^2 + 33^2 .

It is a junction number, because it is equal to n+sod(n) for n = 311202202091 and 311202202100.

It is not an unprimeable number, because it can be changed into a prime (311202202117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77800550527 + ... + 77800550530.

Almost surely, 2311202202114 is an apocalyptic number.

311202202114 is a deficient number, since it is larger than the sum of its proper divisors (155601101060).

311202202114 is a wasteful number, since it uses less digits than its factorization.

311202202114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 155601101059.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 311202202114 its reverse (411202202113), we get a palindrome (722404404227).

Subtracting 311202202114 from its reverse (411202202113), we obtain a palindrome (99999999999).

The spelling of 311202202114 in words is "three hundred eleven billion, two hundred two million, two hundred two thousand, one hundred fourteen".

Divisors: 1 2 155601101057 311202202114