Base | Representation |
---|---|
bin | 1001000011101011010… |
… | …00001011011010110010 |
3 | 1002202021211121112100201 |
4 | 10201311220023122302 |
5 | 20044330021041424 |
6 | 354545102105414 |
7 | 31325046543400 |
oct | 4416550133262 |
9 | 1082254545321 |
10 | 311211112114 |
11 | 10aa90617811 |
12 | 50393b7b26a |
13 | 23468701366 |
14 | 110c4088470 |
15 | 8166a4ed44 |
hex | 4875a0b6b2 |
311211112114 has 48 divisors (see below), whose sum is σ = 573814713600. Its totient is φ = 125962252416.
The previous prime is 311211112103. The next prime is 311211112127. The reversal of 311211112114 is 411211112113.
It is a junction number, because it is equal to n+sod(n) for n = 311211112091 and 311211112100.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 695799 + ... + 1051930.
It is an arithmetic number, because the mean of its divisors is an integer number (11954473200).
Almost surely, 2311211112114 is an apocalyptic number.
311211112114 is a deficient number, since it is larger than the sum of its proper divisors (262603601486).
311211112114 is a wasteful number, since it uses less digits than its factorization.
311211112114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1747847 (or 1747840 counting only the distinct ones).
The product of its digits is 48, while the sum is 19.
Adding to 311211112114 its reverse (411211112113), we get a palindrome (722422224227).
Subtracting 311211112114 from its reverse (411211112113), we obtain a palindrome (99999999999).
The spelling of 311211112114 in words is "three hundred eleven billion, two hundred eleven million, one hundred twelve thousand, one hundred fourteen".
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