Base | Representation |
---|---|
bin | 100011011000010111000111… |
… | …0011000100101110111110001 |
3 | 1111210220112002020100222100101 |
4 | 1012300232032120211313301 |
5 | 311242341444033041423 |
6 | 3021520315440152401 |
7 | 122360166131161630 |
oct | 10660561630456761 |
9 | 1453815066328311 |
10 | 311211424112113 |
11 | 901860297120a8 |
12 | 2aaa2a38308701 |
13 | 1048615a8a6c95 |
14 | 56bc9db3dd517 |
15 | 25ea4cb3a47ad |
hex | 11b0b8e625df1 |
311211424112113 has 8 divisors (see below), whose sum is σ = 360978709418432. Its totient is φ = 262771266414096.
The previous prime is 311211424112051. The next prime is 311211424112189.
It is a happy number.
311211424112113 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311211424112113 is a prime.
It is not an unprimeable number, because it can be changed into a prime (311211424113113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 331781901570 + ... + 331781902507.
It is an arithmetic number, because the mean of its divisors is an integer number (45122338677304).
Almost surely, 2311211424112113 is an apocalyptic number.
It is an amenable number.
311211424112113 is a deficient number, since it is larger than the sum of its proper divisors (49767285306319).
311211424112113 is an equidigital number, since it uses as much as digits as its factorization.
311211424112113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 663563804151.
The product of its digits is 1152, while the sum is 28.
The spelling of 311211424112113 in words is "three hundred eleven trillion, two hundred eleven billion, four hundred twenty-four million, one hundred twelve thousand, one hundred thirteen".
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