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311212130223 = 3103737376741
BaseRepresentation
bin1001000011101011011…
…00000011111110101111
31002202021220112020221110
410201311230003332233
520044330301131343
6354545140003103
731325061313551
oct4416554037657
91082256466843
10311212130223
1110aa91152725
1250394390493
13234689998a7
14110c42714d1
158166ba1833
hex4875b03faf

311212130223 has 4 divisors (see below), whose sum is σ = 414949506968. Its totient is φ = 207474753480.

The previous prime is 311212130221. The next prime is 311212130231. The reversal of 311212130223 is 322031212113.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 311212130223 - 21 = 311212130221 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 311212130223.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311212130221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51868688368 + ... + 51868688373.

It is an arithmetic number, because the mean of its divisors is an integer number (103737376742).

Almost surely, 2311212130223 is an apocalyptic number.

311212130223 is a deficient number, since it is larger than the sum of its proper divisors (103737376745).

311212130223 is a wasteful number, since it uses less digits than its factorization.

311212130223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103737376744.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 311212130223 its reverse (322031212113), we get a palindrome (633243342336).

The spelling of 311212130223 in words is "three hundred eleven billion, two hundred twelve million, one hundred thirty thousand, two hundred twenty-three".

Divisors: 1 3 103737376741 311212130223