3112122113 has 4 divisors (see below), whose sum is σ = 3112280880. Its totient is φ = 3111963348.

The previous prime is 3112122073. The next prime is 3112122127. The reversal of 3112122113 is 3112212113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3112212113 = 47 ⋅66217279.

It is a cyclic number.

It is not a de Polignac number, because 3112122113 - 2¹⁴ = 3112105729 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 3112122091 and 3112122100.

It is not an unprimeable number, because it can be changed into a prime (3112122193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45023 + ... + 90836.

It is an arithmetic number, because the mean of its divisors is an integer number (778070220).

Almost surely, 2^3112122113 is an apocalyptic number.

It is an amenable number.

3112122113 is a deficient number, since it is larger than the sum of its proper divisors (158767).

3112122113 is a wasteful number, since it uses less digits than its factorization.

3112122113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 158766.

The product of its digits is 72, while the sum is 17.

The square root of 3112122113 is about 55786.3972039780. The cubic root of 3112122113 is about 1459.9978283886.

Adding to 3112122113 its reverse (3112212113), we get a palindrome (6224334226).

Subtracting 3112122113 from its reverse (3112212113), we obtain a square (90000 = 300²).

The spelling of 3112122113 in words is "three billion, one hundred twelve million, one hundred twenty-two thousand, one hundred thirteen".