Base | Representation |
---|---|
bin | 1001000011101011011… |
… | …00011000000001001111 |
3 | 1002202021220200102112110 |
4 | 10201311230120001033 |
5 | 20044330311243203 |
6 | 354545141435103 |
7 | 31325062105056 |
oct | 4416554300117 |
9 | 1082256612473 |
10 | 311212212303 |
11 | 10aa911a9363 |
12 | 5039440ba93 |
13 | 234689c8065 |
14 | 110c429339d |
15 | 8166bbad03 |
hex | 4875b1804f |
311212212303 has 4 divisors (see below), whose sum is σ = 414949616408. Its totient is φ = 207474808200.
The previous prime is 311212212277. The next prime is 311212212307. The reversal of 311212212303 is 303212212113.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 311212212303 - 213 = 311212204111 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 311212212303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311212212307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51868702048 + ... + 51868702053.
It is an arithmetic number, because the mean of its divisors is an integer number (103737404102).
Almost surely, 2311212212303 is an apocalyptic number.
311212212303 is a deficient number, since it is larger than the sum of its proper divisors (103737404105).
311212212303 is a wasteful number, since it uses less digits than its factorization.
311212212303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 103737404104.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 311212212303 its reverse (303212212113), we get a palindrome (614424424416).
The spelling of 311212212303 in words is "three hundred eleven billion, two hundred twelve million, two hundred twelve thousand, three hundred three".
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