Base | Representation |
---|---|
bin | 1110001001101111110010… |
… | …11001010001101000010001 |
3 | 11002012011022111002121021220 |
4 | 13010313321121101220101 |
5 | 13034342230341241423 |
6 | 150104520410235253 |
7 | 6361301620060245 |
oct | 704677131215021 |
9 | 132164274077256 |
10 | 31121222212113 |
11 | 9a09488679120 |
12 | 35a7602425b29 |
13 | 1449945b92887 |
14 | 7983bd1ac425 |
15 | 38e80396c9e3 |
hex | 1c4df9651a11 |
31121222212113 has 8 divisors (see below), whose sum is σ = 45267232308576. Its totient is φ = 18861346795200.
The previous prime is 31121222212103. The next prime is 31121222212139.
31121222212113 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 31121222212113 - 24 = 31121222212097 is a prime.
It is not an unprimeable number, because it can be changed into a prime (31121222212103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 471533669848 + ... + 471533669913.
It is an arithmetic number, because the mean of its divisors is an integer number (5658404038572).
Almost surely, 231121222212113 is an apocalyptic number.
31121222212113 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
31121222212113 is a deficient number, since it is larger than the sum of its proper divisors (14146010096463).
31121222212113 is a wasteful number, since it uses less digits than its factorization.
31121222212113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 943067339775.
The product of its digits is 576, while the sum is 24.
It can be divided in two parts, 3112122 and 2212113, that added together give a palindrome (5324235).
The spelling of 31121222212113 in words is "thirty-one trillion, one hundred twenty-one billion, two hundred twenty-two million, two hundred twelve thousand, one hundred thirteen".
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