31121401431 has 4 divisors (see below), whose sum is σ = 41495201912. Its totient is φ = 20747600952.

The previous prime is 31121401357. The next prime is 31121401463. The reversal of 31121401431 is 13410412113.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 31121401431 - 2¹⁹ = 31120877143 is a prime.

It is a super-2 number, since 2×31121401431² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31121401398 and 31121401407.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31121401471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5186900236 + ... + 5186900241.

It is an arithmetic number, because the mean of its divisors is an integer number (10373800478).

Almost surely, 2^31121401431 is an apocalyptic number.

31121401431 is a deficient number, since it is larger than the sum of its proper divisors (10373800481).

31121401431 is a wasteful number, since it uses less digits than its factorization.

31121401431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10373800480.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 31121401431 its reverse (13410412113), we get a palindrome (44531813544).

The spelling of 31121401431 in words is "thirty-one billion, one hundred twenty-one million, four hundred one thousand, four hundred thirty-one".