Base | Representation |
---|---|
bin | 1011100110000000… |
… | …1011110100111101 |
3 | 22000220012020222222 |
4 | 2321200023310331 |
5 | 22333212101023 |
6 | 1232453415125 |
7 | 140060310365 |
oct | 27140136475 |
9 | 8026166888 |
10 | 3112222013 |
11 | 135784a50a |
12 | 72a33a4a5 |
13 | 3a7a170b4 |
14 | 2174999a5 |
15 | 13335ecc8 |
hex | b980bd3d |
3112222013 has 8 divisors (see below), whose sum is σ = 3186339960. Its totient is φ = 3038849280.
The previous prime is 3112221997. The next prime is 3112222019. The reversal of 3112222013 is 3102222113.
It can be written as a sum of positive squares in 4 ways, for example, as 190495204 + 2921726809 = 13802^2 + 54053^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3112222013 - 24 = 3112221997 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3112221982 and 3112222000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3112222019) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 177848 + ... + 194561.
It is an arithmetic number, because the mean of its divisors is an integer number (398292495).
Almost surely, 23112222013 is an apocalyptic number.
It is an amenable number.
3112222013 is a deficient number, since it is larger than the sum of its proper divisors (74117947).
3112222013 is a wasteful number, since it uses less digits than its factorization.
3112222013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 372607.
The product of its (nonzero) digits is 144, while the sum is 17.
The square root of 3112222013 is about 55787.2925763565. The cubic root of 3112222013 is about 1460.0134503358.
Adding to 3112222013 its reverse (3102222113), we get a palindrome (6214444126).
It can be divided in two parts, 31122 and 22013, that added together give a palindrome (53135).
The spelling of 3112222013 in words is "three billion, one hundred twelve million, two hundred twenty-two thousand, thirteen".
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