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311222222114 = 2155611111057
BaseRepresentation
bin1001000011101100100…
…10100011110100100010
31002202022121111222102012
410201312102203310202
520044340342101424
6354550140152522
731325243145146
oct4416622436442
91082277458365
10311222222114
1110aa96915931
1250397838742
132346aac121b
14110c573b226
1581679e6b0e
hex48764a3d22

311222222114 has 4 divisors (see below), whose sum is σ = 466833333174. Its totient is φ = 155611111056.

The previous prime is 311222222099. The next prime is 311222222117. The reversal of 311222222114 is 411222222113.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 261975067225 + 49247154889 = 511835^2 + 221917^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 311222222114.

It is not an unprimeable number, because it can be changed into a prime (311222222117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77805555527 + ... + 77805555530.

Almost surely, 2311222222114 is an apocalyptic number.

311222222114 is a deficient number, since it is larger than the sum of its proper divisors (155611111060).

311222222114 is a wasteful number, since it uses less digits than its factorization.

311222222114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 155611111059.

The product of its digits is 768, while the sum is 23.

Adding to 311222222114 its reverse (411222222113), we get a palindrome (722444444227).

Subtracting 311222222114 from its reverse (411222222113), we obtain a palindrome (99999999999).

The spelling of 311222222114 in words is "three hundred eleven billion, two hundred twenty-two million, two hundred twenty-two thousand, one hundred fourteen".

Divisors: 1 2 155611111057 311222222114