Base | Representation |
---|---|
bin | 1110001001110001110011… |
… | …01100111010011110110011 |
3 | 11002012021002200012212222201 |
4 | 13010320321230322132303 |
5 | 13034401433040231003 |
6 | 150105215430444031 |
7 | 6361340430351646 |
oct | 704707154723663 |
9 | 132167080185881 |
10 | 31122301102003 |
11 | 9a09991685061 |
12 | 35a7863803617 |
13 | 1449a88561a67 |
14 | 7984825b3a5d |
15 | 38e868533b1d |
hex | 1c4e39b3a7b3 |
31122301102003 has 32 divisors (see below), whose sum is σ = 32484920832000. Its totient is φ = 29793792314880.
The previous prime is 31122301102001. The next prime is 31122301102043. The reversal of 31122301102003 is 30020110322113.
It is a cyclic number.
It is not a de Polignac number, because 31122301102003 - 21 = 31122301102001 is a prime.
It is a super-3 number, since 3×311223011020033 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31122301102001) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1379095426 + ... + 1379117992.
It is an arithmetic number, because the mean of its divisors is an integer number (1015153776000).
Almost surely, 231122301102003 is an apocalyptic number.
31122301102003 is a deficient number, since it is larger than the sum of its proper divisors (1362619729997).
31122301102003 is a wasteful number, since it uses less digits than its factorization.
31122301102003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25555.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 31122301102003 its reverse (30020110322113), we get a palindrome (61142411424116).
The spelling of 31122301102003 in words is "thirty-one trillion, one hundred twenty-two billion, three hundred one million, one hundred two thousand, three".
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