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3112230132000 = 2532531141672861
BaseRepresentation
bin101101010010011111010…
…111110001100100100000
3102000112012200001200210200
4231102133113301210200
5401442321403211000
610341423324425200
7440564651432103
oct55223727614440
912015180050720
103112230132000
11a9a986856a90
124232076a8200
1319763607b532
14aa8c035c73a
1555e5250b500
hex2d49f5f1920

3112230132000 has 1152 divisors, whose sum is σ = 12531918986496. Its totient is φ = 724838400000.

The previous prime is 3112230131993. The next prime is 3112230132047. The reversal of 3112230132000 is 2310322113.

3112230132000 is a `hidden beast` number, since 3 + 112 + 230 + 1 + 320 + 0 + 0 = 666.

3112230132000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 1087810570 + ... + 1087813430.

It is an arithmetic number, because the mean of its divisors is an integer number (10878401898).

Almost surely, 23112230132000 is an apocalyptic number.

3112230132000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3112230132000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (6265959493248).

3112230132000 is an abundant number, since it is smaller than the sum of its proper divisors (9419688854496).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3112230132000 is a wasteful number, since it uses less digits than its factorization.

3112230132000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3011 (or 2990 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 3112230132000 its reverse (2310322113), we get a palindrome (3114540454113).

The spelling of 3112230132000 in words is "three trillion, one hundred twelve billion, two hundred thirty million, one hundred thirty-two thousand".