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31124976053 = 375914257891
BaseRepresentation
bin11100111111001100…
…010111000110110101
32222100011010121101212
4130333030113012311
51002220443213203
622144300131205
72151206634263
oct347714270665
988304117355
1031124976053
1112222268206
126047836b05
132c2047c0c2
141713a09433
15c227951d8
hex73f3171b5

31124976053 has 8 divisors (see below), whose sum is σ = 32507993760. Its totient is φ = 29770474320.

The previous prime is 31124976017. The next prime is 31124976083. The reversal of 31124976053 is 35067942113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 31124976053 - 212 = 31124971957 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 31124976053.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31124976083) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7126763 + ... + 7131128.

It is an arithmetic number, because the mean of its divisors is an integer number (4063499220).

Almost surely, 231124976053 is an apocalyptic number.

It is an amenable number.

31124976053 is a deficient number, since it is larger than the sum of its proper divisors (1383017707).

31124976053 is a wasteful number, since it uses less digits than its factorization.

31124976053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14257987.

The product of its (nonzero) digits is 136080, while the sum is 41.

The spelling of 31124976053 in words is "thirty-one billion, one hundred twenty-four million, nine hundred seventy-six thousand, fifty-three".

Divisors: 1 37 59 2183 14257891 527541967 841215569 31124976053