Base | Representation |
---|---|
bin | 100011011000101011100110… |
… | …1111101011111000111000010 |
3 | 1111211001201200210211011022111 |
4 | 1012301113031331133013002 |
5 | 311244102120221440224 |
6 | 3021552435250325534 |
7 | 122363314654503664 |
oct | 10661271575370702 |
9 | 1454051623734274 |
10 | 311255440421314 |
11 | 901a2766783744 |
12 | 2aaab4812898aa |
13 | 1048a353a6b45c |
14 | 56c0bb5168534 |
15 | 25eb705783d94 |
hex | 11b15cdf5f1c2 |
311255440421314 has 8 divisors (see below), whose sum is σ = 467775862661520. Its totient is φ = 155330152867476.
The previous prime is 311255440421297. The next prime is 311255440421347. The reversal of 311255440421314 is 413124044552113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×3112554404213142 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 148783670284 + ... + 148783672375.
It is an arithmetic number, because the mean of its divisors is an integer number (58471982832690).
Almost surely, 2311255440421314 is an apocalyptic number.
311255440421314 is a deficient number, since it is larger than the sum of its proper divisors (156520422240206).
311255440421314 is a wasteful number, since it uses less digits than its factorization.
311255440421314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 297567343184.
The product of its (nonzero) digits is 230400, while the sum is 40.
Adding to 311255440421314 its reverse (413124044552113), we get a palindrome (724379484973427).
The spelling of 311255440421314 in words is "three hundred eleven trillion, two hundred fifty-five billion, four hundred forty million, four hundred twenty-one thousand, three hundred fourteen".
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