Base | Representation |
---|---|
bin | 1001000011110101110… |
… | …11101011111010000010 |
3 | 1002202112001002012020212 |
4 | 10201322323223322002 |
5 | 20100020312041002 |
6 | 355002001434122 |
7 | 31330210202315 |
oct | 4417273537202 |
9 | 1082461065225 |
10 | 311300112002 |
11 | 110026885740 |
12 | 503b993b942 |
13 | 23480c93009 |
14 | 110d1c1497c |
15 | 816e780352 |
hex | 487aeebe82 |
311300112002 has 8 divisors (see below), whose sum is σ = 509400183312. Its totient is φ = 141500050900.
The previous prime is 311300112001. The next prime is 311300112041. The reversal of 311300112002 is 200211003113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not an unprimeable number, because it can be changed into a prime (311300112001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7075002524 + ... + 7075002567.
It is an arithmetic number, because the mean of its divisors is an integer number (63675022914).
Almost surely, 2311300112002 is an apocalyptic number.
311300112002 is a deficient number, since it is larger than the sum of its proper divisors (198100071310).
311300112002 is a wasteful number, since it uses less digits than its factorization.
311300112002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14150005104.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 311300112002 its reverse (200211003113), we get a palindrome (511511115115).
The spelling of 311300112002 in words is "three hundred eleven billion, three hundred million, one hundred twelve thousand, two".
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