311300113 has 4 divisors (see below), whose sum is σ = 311335920. Its totient is φ = 311264308.

The previous prime is 311300089. The next prime is 311300131. The reversal of 311300113 is 311003113.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 311003113 = 89 ⋅3494417.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-311300113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 311300093 and 311300102.

It is not an unprimeable number, because it can be changed into a prime (311300173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4398 + ... + 25336.

It is an arithmetic number, because the mean of its divisors is an integer number (77833980).

Almost surely, 2^311300113 is an apocalyptic number.

It is an amenable number.

311300113 is a deficient number, since it is larger than the sum of its proper divisors (35807).

311300113 is a wasteful number, since it uses less digits than its factorization.

311300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35806.

The product of its (nonzero) digits is 27, while the sum is 13.

The square root of 311300113 is about 17643.6989602521. The cubic root of 311300113 is about 677.7347583125.

Adding to 311300113 its reverse (311003113), we get a palindrome (622303226).

The spelling of 311300113 in words is "three hundred eleven million, three hundred thousand, one hundred thirteen".