Base | Representation |
---|---|
bin | 1011100110001100… |
… | …1010110001110011 |
3 | 22000221122222212220 |
4 | 2321203022301303 |
5 | 22333412113042 |
6 | 1232522252123 |
7 | 140100045561 |
oct | 27143126163 |
9 | 8027588786 |
10 | 3113004147 |
11 | 1358234100 |
12 | 72a657043 |
13 | 3a7c2c0b6 |
14 | 217620a31 |
15 | 1334668ec |
hex | b98cac73 |
3113004147 has 24 divisors (see below), whose sum is σ = 4830689808. Its totient is φ = 1775685120.
The previous prime is 3113004127. The next prime is 3113004149. The reversal of 3113004147 is 7414003113.
It is not a de Polignac number, because 3113004147 - 27 = 3113004019 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3113004149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 246058 + ... + 258399.
It is an arithmetic number, because the mean of its divisors is an integer number (201278742).
Almost surely, 23113004147 is an apocalyptic number.
3113004147 is a deficient number, since it is larger than the sum of its proper divisors (1717685661).
3113004147 is a wasteful number, since it uses less digits than its factorization.
3113004147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 504499 (or 504488 counting only the distinct ones).
The product of its (nonzero) digits is 1008, while the sum is 24.
The square root of 3113004147 is about 55794.3021015587. The cubic root of 3113004147 is about 1460.1357456508.
The spelling of 3113004147 in words is "three billion, one hundred thirteen million, four thousand, one hundred forty-seven".
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