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31130100223 = 89349776407
BaseRepresentation
bin11100111111011111…
…111010000111111111
32222100111202221102221
4130333133322013333
51002223301201343
622145002030211
72151301325455
oct347737720777
988314687387
1031130100223
1112225148062
1260494a8367
132c21554561
1417145809d5
15c22e585ed
hex73f7fa1ff

31130100223 has 4 divisors (see below), whose sum is σ = 31479876720. Its totient is φ = 30780323728.

The previous prime is 31130100167. The next prime is 31130100277. The reversal of 31130100223 is 32200103113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 31130100223 - 225 = 31096545791 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31130100197 and 31130100206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31130100623) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 174888115 + ... + 174888292.

It is an arithmetic number, because the mean of its divisors is an integer number (7869969180).

Almost surely, 231130100223 is an apocalyptic number.

31130100223 is a deficient number, since it is larger than the sum of its proper divisors (349776497).

31130100223 is an equidigital number, since it uses as much as digits as its factorization.

31130100223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 349776496.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 31130100223 its reverse (32200103113), we get a palindrome (63330203336).

The spelling of 31130100223 in words is "thirty-one billion, one hundred thirty million, one hundred thousand, two hundred twenty-three".

Divisors: 1 89 349776407 31130100223