3113010103113 has 12 divisors (see below), whose sum is σ = 4498724737728. Its totient is φ = 2074345643160.

The previous prime is 3113010103081. The next prime is 3113010103121.

3113010103113 is a `hidden beast` number, since 311 + 30 + 1 + 0 + 10 + 311 + 3 = 666.

3113010103113 is nontrivially palindromic in base 10.

3113010103113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 3113010103113 - 2⁵ = 3113010103081 is a prime.

It is a super-2 number, since 2×3113010103113² (a number of 26 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (3113010103123) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 82848973 + ... + 82886538.

It is an arithmetic number, because the mean of its divisors is an integer number (374893728144).

Almost surely, 2^{3113010103113} is an apocalyptic number.

It is an amenable number.

3113010103113 is a deficient number, since it is larger than the sum of its proper divisors (1385714634615).

3113010103113 is a wasteful number, since it uses less digits than its factorization.

3113010103113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 165737604 (or 165737601 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 18.

It can be divided in two parts, 3113010 and 103113, that added together give a palindrome (3216123).

The spelling of 3113010103113 in words is "three trillion, one hundred thirteen billion, ten million, one hundred three thousand, one hundred thirteen".