Base | Representation |
---|---|
bin | 11100111111100001… |
… | …011011110010110011 |
3 | 2222100112112021012200 |
4 | 130333201123302303 |
5 | 1002223402002100 |
6 | 22145014354243 |
7 | 2151304613010 |
oct | 347741336263 |
9 | 88315467180 |
10 | 31130500275 |
11 | 122253a0686 |
12 | 604965b983 |
13 | 2c21664684 |
14 | 1714646707 |
15 | c22ed6e00 |
hex | 73f85bcb3 |
31130500275 has 72 divisors (see below), whose sum is σ = 64354895904. Its totient is φ = 14090112000.
The previous prime is 31130500259. The next prime is 31130500339. The reversal of 31130500275 is 57200503113.
31130500275 is a `hidden beast` number, since 3 + 1 + 130 + 500 + 27 + 5 = 666.
It is not a de Polignac number, because 31130500275 - 24 = 31130500259 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 61227 + ... + 256923.
Almost surely, 231130500275 is an apocalyptic number.
31130500275 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
31130500275 is an abundant number, since it is smaller than the sum of its proper divisors (33224395629).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31130500275 is a wasteful number, since it uses less digits than its factorization.
31130500275 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 195821 (or 195813 counting only the distinct ones).
The product of its (nonzero) digits is 3150, while the sum is 27.
The spelling of 31130500275 in words is "thirty-one billion, one hundred thirty million, five hundred thousand, two hundred seventy-five".
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