Base | Representation |
---|---|
bin | 1110001010000010000000… |
… | …01101000000000011000111 |
3 | 11002020002112220221100101100 |
4 | 13011001000031000003013 |
5 | 13040022242012030203 |
6 | 150113214540431143 |
7 | 6362066126616051 |
oct | 705010015000307 |
9 | 132202486840340 |
10 | 31131000111303 |
11 | 9a12645a85544 |
12 | 35a9490b484b3 |
13 | 144a843858341 |
14 | 798a69a388d1 |
15 | 38ebc70a7ea3 |
hex | 1c50403400c7 |
31131000111303 has 6 divisors (see below), whose sum is σ = 44967000160784. Its totient is φ = 20754000074196.
The previous prime is 31131000111181. The next prime is 31131000111307. The reversal of 31131000111303 is 30311100013113.
31131000111303 is a `hidden beast` number, since 311 + 310 + 0 + 0 + 1 + 11 + 30 + 3 = 666.
It is not a de Polignac number, because 31131000111303 - 214 = 31131000094919 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31131000111307) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1729500006175 + ... + 1729500006192.
Almost surely, 231131000111303 is an apocalyptic number.
31131000111303 is a deficient number, since it is larger than the sum of its proper divisors (13836000049481).
31131000111303 is a wasteful number, since it uses less digits than its factorization.
31131000111303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3459000012373 (or 3459000012370 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 18.
Adding to 31131000111303 its reverse (30311100013113), we get a palindrome (61442100124416).
The spelling of 31131000111303 in words is "thirty-one trillion, one hundred thirty-one billion, one hundred eleven thousand, three hundred three".
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