31131205425439 has 8 divisors (see below), whose sum is σ = 37671374632608. Its totient is φ = 25114249754880.

The previous prime is 31131205425367. The next prime is 31131205425443. The reversal of 31131205425439 is 93452450213113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 31131205425439 - 2²¹ = 31131203328287 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31131205425395 and 31131205425404.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31131205435439) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 130803384022 + ... + 130803384259.

It is an arithmetic number, because the mean of its divisors is an integer number (4708921829076).

Almost surely, 2^{31131205425439} is an apocalyptic number.

31131205425439 is a deficient number, since it is larger than the sum of its proper divisors (6540169207169).

31131205425439 is a wasteful number, since it uses less digits than its factorization.

31131205425439 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 261606768305.

The product of its (nonzero) digits is 388800, while the sum is 43.

The spelling of 31131205425439 in words is "thirty-one trillion, one hundred thirty-one billion, two hundred five million, four hundred twenty-five thousand, four hundred thirty-nine".