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311312103 = 3103770701
BaseRepresentation
bin10010100011100…
…011111011100111
3210200210021220220
4102203203323213
51114143441403
650520255423
710500052314
oct2243437347
9720707826
10311312103
1114a800433
1288311573
134c65b95b
142d4b9d0b
151c4e5953
hex128e3ee7

311312103 has 4 divisors (see below), whose sum is σ = 415082808. Its totient is φ = 207541400.

The previous prime is 311312101. The next prime is 311312171. The reversal of 311312103 is 301213113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 311312103 - 21 = 311312101 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311312101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51885348 + ... + 51885353.

It is an arithmetic number, because the mean of its divisors is an integer number (103770702).

Almost surely, 2311312103 is an apocalyptic number.

311312103 is a deficient number, since it is larger than the sum of its proper divisors (103770705).

311312103 is a wasteful number, since it uses less digits than its factorization.

311312103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 103770704.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 311312103 is about 17644.0387383388. The cubic root of 311312103 is about 677.7434593859.

Adding to 311312103 its reverse (301213113), we get a palindrome (612525216).

The spelling of 311312103 in words is "three hundred eleven million, three hundred twelve thousand, one hundred three".

Divisors: 1 3 103770701 311312103