Base | Representation |
---|---|
bin | 101101010011010100100… |
… | …010011110110101111011 |
3 | 102000121111211111221211122 |
4 | 231103110202132311323 |
5 | 402001133231200243 |
6 | 10342052031215455 |
7 | 440626032336161 |
oct | 55232442366573 |
9 | 12017454457748 |
10 | 3113122131323 |
11 | aa02a4314306 |
12 | 42341637758b |
13 | 197748b03399 |
14 | aa9669d5231 |
15 | 55ea59a7668 |
hex | 2d4d489ed7b |
3113122131323 has 4 divisors (see below), whose sum is σ = 3118167710760. Its totient is φ = 3108076551888.
The previous prime is 3113122131307. The next prime is 3113122131331. The reversal of 3113122131323 is 3231312213113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3113122131323 - 24 = 3113122131307 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3113122131292 and 3113122131301.
It is not an unprimeable number, because it can be changed into a prime (3113122121323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2522788793 + ... + 2522790026.
It is an arithmetic number, because the mean of its divisors is an integer number (779541927690).
Almost surely, 23113122131323 is an apocalyptic number.
3113122131323 is a deficient number, since it is larger than the sum of its proper divisors (5045579437).
3113122131323 is an equidigital number, since it uses as much as digits as its factorization.
3113122131323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5045579436.
The product of its digits is 1944, while the sum is 26.
Adding to 3113122131323 its reverse (3231312213113), we get a palindrome (6344434344436).
The spelling of 3113122131323 in words is "three trillion, one hundred thirteen billion, one hundred twenty-two million, one hundred thirty-one thousand, three hundred twenty-three".
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