3113122131331 has 2 divisors, whose sum is σ = 3113122131332. Its totient is φ = 3113122131330.

The previous prime is 3113122131307. The next prime is 3113122131337. The reversal of 3113122131331 is 1331312213113.

3113122131331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3113122131331 - 2¹⁵ = 3113122098563 is a prime.

It is a super-2 number, since 2×3113122131331² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3113122131296 and 3113122131305.

It is not a weakly prime, because it can be changed into another prime (3113122131337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556561065665 + 1556561065666.

It is an arithmetic number, because the mean of its divisors is an integer number (1556561065666).

Almost surely, 2^{3113122131331} is an apocalyptic number.

3113122131331 is a deficient number, since it is larger than the sum of its proper divisors (1).

3113122131331 is an equidigital number, since it uses as much as digits as its factorization.

3113122131331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 972, while the sum is 25.

Adding to 3113122131331 its reverse (1331312213113), we get a palindrome (4444434344444).

The spelling of 3113122131331 in words is "three trillion, one hundred thirteen billion, one hundred twenty-two million, one hundred thirty-one thousand, three hundred thirty-one".