Base | Representation |
---|---|
bin | 101101010011010100101… |
… | …111100001101110011010 |
3 | 102000121112001221200202102 |
4 | 231103110233201232122 |
5 | 402001140120113002 |
6 | 10342052232403402 |
7 | 440626103401115 |
oct | 55232457415632 |
9 | 12017461850672 |
10 | 3113125551002 |
11 | aa02a623a595 |
12 | 423417546562 |
13 | 19774972ca6c |
14 | aa96724557c |
15 | 55ea5e30a02 |
hex | 2d4d4be1b9a |
3113125551002 has 4 divisors (see below), whose sum is σ = 4669688326506. Its totient is φ = 1556562775500.
The previous prime is 3113125550993. The next prime is 3113125551073. The reversal of 3113125551002 is 2001555213113.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 2393700971281 + 719424579721 = 1547159^2 + 848189^2 .
It is a super-2 number, since 2×31131255510022 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 778281387749 + ... + 778281387752.
Almost surely, 23113125551002 is an apocalyptic number.
3113125551002 is a deficient number, since it is larger than the sum of its proper divisors (1556562775504).
3113125551002 is a wasteful number, since it uses less digits than its factorization.
3113125551002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1556562775503.
The product of its (nonzero) digits is 4500, while the sum is 29.
The spelling of 3113125551002 in words is "three trillion, one hundred thirteen billion, one hundred twenty-five million, five hundred fifty-one thousand, two".
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