Base | Representation |
---|---|
bin | 100011011001000110011010… |
… | …1100000000001011111001001 |
3 | 1111211021020022002002121201120 |
4 | 1012302030311200001133021 |
5 | 311301023022044244423 |
6 | 3022035120131305453 |
7 | 122400423436642536 |
oct | 10662146540013711 |
9 | 1454236262077646 |
10 | 311313012103113 |
11 | 9021511a467359 |
12 | 2aaba669a4b289 |
13 | 104928ca3a6367 |
14 | 56c38b7309d8d |
15 | 25ece74c19ee3 |
hex | 11b23358017c9 |
311313012103113 has 8 divisors (see below), whose sum is σ = 415341992536800. Its totient is φ = 207413019869088.
The previous prime is 311313012103073. The next prime is 311313012103133. The reversal of 311313012103113 is 311301210313113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 311313012103113 - 210 = 311313012102089 is a prime.
It is not an unprimeable number, because it can be changed into a prime (311313012103133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32247044283 + ... + 32247053936.
It is an arithmetic number, because the mean of its divisors is an integer number (51917749067100).
Almost surely, 2311313012103113 is an apocalyptic number.
It is an amenable number.
311313012103113 is a deficient number, since it is larger than the sum of its proper divisors (104028980433687).
311313012103113 is a wasteful number, since it uses less digits than its factorization.
311313012103113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 64494099831.
The product of its (nonzero) digits is 486, while the sum is 24.
Adding to 311313012103113 its reverse (311301210313113), we get a palindrome (622614222416226).
The spelling of 311313012103113 in words is "three hundred eleven trillion, three hundred thirteen billion, twelve million, one hundred three thousand, one hundred thirteen".
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