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3113140305151 = 171631123471781
BaseRepresentation
bin101101010011010101100…
…111110011110011111111
3102000121120002201021122101
4231103111213303303333
5402001202404231101
610342053520525531
7440626342661122
oct55232547636377
912017502637571
103113140305151
11aa03035a75a8
124234204808a7
1319774c7c7526
14aa9691a63b9
1555ea7397401
hex2d4d59f3cff

3113140305151 has 8 divisors (see below), whose sum is σ = 3316488700464. Its totient is φ = 2912038853760.

The previous prime is 3113140305139. The next prime is 3113140305161. The reversal of 3113140305151 is 1515030413113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3113140305151 - 29 = 3113140304639 is a prime.

It is a super-2 number, since 2×31131403051512 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3113140305131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 561733120 + ... + 561738661.

It is an arithmetic number, because the mean of its divisors is an integer number (414561087558).

Almost surely, 23113140305151 is an apocalyptic number.

3113140305151 is a deficient number, since it is larger than the sum of its proper divisors (203348395313).

3113140305151 is a wasteful number, since it uses less digits than its factorization.

3113140305151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1123471961.

The product of its (nonzero) digits is 2700, while the sum is 28.

Adding to 3113140305151 its reverse (1515030413113), we get a palindrome (4628170718264).

The spelling of 3113140305151 in words is "three trillion, one hundred thirteen billion, one hundred forty million, three hundred five thousand, one hundred fifty-one".

Divisors: 1 17 163 2771 1123471781 19099020277 183125900303 3113140305151