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311314114 = 2155657057
BaseRepresentation
bin10010100011100…
…100011011000010
3210200210101200101
4102203210123002
51114144022424
650520313014
710500061216
oct2243443302
9720711611
10311314114
1114a8019a1
128831276a
134c65c847
142d4ba946
151c4e6344
hex128e46c2

311314114 has 4 divisors (see below), whose sum is σ = 466971174. Its totient is φ = 155657056.

The previous prime is 311314111. The next prime is 311314117. The reversal of 311314114 is 411413113.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (311314111) and next prime (311314117).

It can be written as a sum of positive squares in only one way, i.e., 269517889 + 41796225 = 16417^2 + 6465^2 .

It is a junction number, because it is equal to n+sod(n) for n = 311314091 and 311314100.

It is not an unprimeable number, because it can be changed into a prime (311314111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77828527 + ... + 77828530.

Almost surely, 2311314114 is an apocalyptic number.

311314114 is a deficient number, since it is larger than the sum of its proper divisors (155657060).

311314114 is a wasteful number, since it uses less digits than its factorization.

311314114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 155657059.

The product of its digits is 144, while the sum is 19.

The square root of 311314114 is about 17644.0957263329. The cubic root of 311314114 is about 677.7449187351.

Adding to 311314114 its reverse (411413113), we get a palindrome (722727227).

It can be divided in two parts, 31131 and 4114, that added together give a triangular number (35245 = T265).

The spelling of 311314114 in words is "three hundred eleven million, three hundred fourteen thousand, one hundred fourteen".

Divisors: 1 2 155657057 311314114