Base | Representation |
---|---|
bin | 1110001010000010110001… |
… | …11001001010111011101011 |
3 | 11002020010121210101111222222 |
4 | 13011001120321022323223 |
5 | 13040024114032442103 |
6 | 150113324015104255 |
7 | 6362112316544603 |
oct | 705013071127353 |
9 | 132203553344888 |
10 | 31131414343403 |
11 | 9a12838891220 |
12 | 35a958781208b |
13 | 144a8ab6108aa |
14 | 798aa8a65c03 |
15 | 38ebed62d638 |
hex | 1c5058e4aeeb |
31131414343403 has 64 divisors (see below), whose sum is σ = 37898156703744. Its totient is φ = 25224741696000.
The previous prime is 31131414343373. The next prime is 31131414343441. The reversal of 31131414343403 is 30434341413113.
It is not a de Polignac number, because 31131414343403 - 216 = 31131414277867 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31131414348403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 173244800 + ... + 173424402.
It is an arithmetic number, because the mean of its divisors is an integer number (592158698496).
Almost surely, 231131414343403 is an apocalyptic number.
31131414343403 is a deficient number, since it is larger than the sum of its proper divisors (6766742360341).
31131414343403 is a wasteful number, since it uses less digits than its factorization.
31131414343403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 180056.
The product of its (nonzero) digits is 62208, while the sum is 35.
Adding to 31131414343403 its reverse (30434341413113), we get a palindrome (61565755756516).
The spelling of 31131414343403 in words is "thirty-one trillion, one hundred thirty-one billion, four hundred fourteen million, three hundred forty-three thousand, four hundred three".
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